x^2-435x+40500=0

Solution for x^2-435x+40500=0 equation:

x^2-435x+40500=0

a = 1; b = -435; c = +40500;
Δ = b2-4ac
Δ = -4352-4·1·40500
Δ = 27225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{27225}=165$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-435)-165}{2*1}=\frac{270}{2}
=135
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-435)+165}{2*1}=\frac{600}{2}
=300
$